⚗️ Full Lesson · Reaction Mechanisms
Strong Base + Heat · Anti-Periplanar · Zaitsev
E2 Elimination

A single concerted step that removes a proton and a leaving group simultaneously, but only when the geometry lines up exactly right.

THE CONCEPT
A Concerted Removal With a Strict Geometric Requirement

E2 (elimination, bimolecular) removes a hydrogen from one carbon and a leaving group from the adjacent carbon in a single concerted step, forming a new pi bond between those two carbons as both groups depart simultaneously. Like SN2, this is a one-step mechanism with no intermediate, and it requires the base to actively participate in the same step the leaving group departs.

Unlike a simple substitution, E2 has a strict geometric requirement that determines whether the reaction can proceed at all: the hydrogen being removed and the leaving group being displaced must be anti-periplanar to each other — positioned 180° apart when viewed down the C-C bond connecting them (exactly the kind of relationship you'd check using a Newman projection). This precise alignment is required because it allows the developing p-orbitals on each carbon to line up correctly as the new pi bond forms, and any other dihedral angle prevents that overlap from developing properly.

💡 Memory Trick
The hub's trick packs the defining features together: E2 = strong bulky base + heat, anti-periplanar geometry, Zaitsev product. A strong, bulky base (rather than a simple, small strong nucleophile) is typically used specifically because bulky bases favor removing a proton (elimination) over attacking carbon directly (substitution), and heat further favors elimination pathways generally, since elimination reactions tend to be entropy-favored (producing more separate product molecules) relative to substitution. The anti-periplanar requirement is the geometric signature unique to E2. And Zaitsev's rule — the more substituted (thermodynamically more stable) alkene is generally the major product — governs which specific elimination product predominates when more than one beta-hydrogen is available for removal.
WHY BULKY BASES PUSH THE REACTION TOWARD ELIMINATION
Steric Bulk Favors Grabbing a Proton Over Attacking Carbon

A bulky base like potassium tert-butoxide has a hard time physically reaching a crowded, sterically hindered carbon to perform a substitution-style attack — but it has a much easier time reaching out to grab a small, exposed hydrogen atom sitting on the outside of the molecule. This steric mismatch is exactly why chemists deliberately choose bulky bases when they want to steer a reaction toward elimination and away from competing substitution, especially on secondary or tertiary substrates where both pathways are otherwise plausible.

This connects directly to the broader SN1/SN2/E1/E2 decision-making framework covered in the next lesson: recognizing a bulky base in a given set of reaction conditions is often the single fastest clue that E2 (rather than SN2) is the intended pathway, even before considering substrate class or solvent at all.

🧪 Lab Application
You're treating 2-bromobutane with potassium tert-butoxide (a strong, bulky base) under heat and need to predict both the mechanism and the major product.
1
Recognize the base as a signal for E2. Potassium tert-butoxide is both strong and sterically bulky, favoring proton removal (elimination) over nucleophilic attack at carbon (substitution).
2
Confirm the reaction proceeds through a single concerted step. With a strong base and heat both present, expect a one-step E2 mechanism, requiring anti-periplanar geometry between the leaving bromide and whichever beta-hydrogen is removed.
3
Identify the possible elimination products. 2-bromobutane has beta-hydrogens available on both sides of the leaving group, potentially forming either 1-butene (less substituted) or 2-butene (more substituted).
4
Apply Zaitsev's rule to predict the major product. Since the more substituted alkene is generally favored as the major product, expect 2-butene to predominate over 1-butene under these standard E2 conditions.
📌 Exam Application
E2 questions often test the anti-periplanar requirement directly by giving you a specific stereoisomer and a specific base, then asking whether elimination can even occur from the drawn conformation — always check the dihedral angle between the leaving group and the candidate beta-hydrogen before predicting a product.
⚠️ Most Common E2 Elimination Mistakes
The most common mistake is applying Zaitsev's rule without first checking whether an anti-periplanar hydrogen is actually available on the more-substituted side — if geometry blocks that particular elimination pathway, the less-substituted (Hofmann) product may form instead, regardless of Zaitsev's general preference. The other frequent trap is confusing a bulky base's role in E2 with its base strength — bulk favors elimination for steric reasons, separate from (though often paired with) genuine base strength.
✓ Quick Self-Test
1) What geometric relationship must exist between the leaving group and the hydrogen being removed in E2? 2) Why do bulky bases favor elimination over substitution? 3) What does Zaitsev's rule predict about the major elimination product? 4) Is E2 a one-step or two-step mechanism? 5) Why does heat generally favor elimination reactions over substitution reactions?
Next Lesson
SN1/SN2/E1/E2 Decision
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