THE CONCEPT
Cyanide as the Nucleophile in the Standard Addition Mechanism
A cyanohydrin forms when cyanide (as the nucleophile CN⁻, typically supplied from NaCN or KCN together with HCN) adds to an aldehyde or ketone via the same universal nucleophilic addition mechanism from earlier in this sub-subject: cyanide's carbon lone pair attacks the electrophilic carbonyl carbon, the carbonyl pi electrons collapse onto oxygen, and protonation during workup gives the final product — a molecule bearing both a hydroxyl and a nitrile group on what was the original carbonyl carbon, written R₂C(OH)CN.
What makes this particular nucleophilic addition especially valuable in synthesis is that cyanide's carbon becomes a genuinely new carbon atom permanently incorporated into the product skeleton — this reaction is one of the small number of nucleophilic additions in this sub-subject that actually extends the carbon count of the molecule, rather than simply installing a new heteroatom-containing group onto an existing carbon skeleton.
💡 Memory Trick
The hub's trick states the transformation directly: a cyanohydrin is HCN adding to a carbonyl, adding one carbon: R₂C(OH)CN. The two follow-up synthetic uses are worth memorizing as a pair: the resulting nitrile (CN) group can be hydrolyzed to a carboxylic acid (COOH) under aqueous acidic or basic conditions, or can be reduced to a primary amine (CH₂NH₂) using a strong reducing agent like LiAlH₄ — meaning a single cyanohydrin intermediate gives a chemist a genuine choice of two very different downstream functional groups from the same starting carbon-extension step.
WHY ALDEHYDES REACT MORE READILY THAN KETONES HERE
Steric and Electronic Effects Working Together
The hub notes directly that aldehydes react more readily than ketones in cyanohydrin formation, and the reaction is thermodynamically favorable with formaldehyde and acetaldehyde specifically, while the equilibrium disfavors cyanohydrin formation with more hindered ketones. This tracks with a combination of two familiar effects working in the same direction: aldehydes are both less sterically hindered (only one substituent plus a hydrogen, versus two substituents on a ketone) and more electronically electrophilic at the carbonyl carbon (a ketone's two alkyl groups donate some electron density inductively, making its carbonyl carbon comparatively less electrophilic than an aldehyde's).
For a bulky, hindered ketone specifically, the equilibrium constant for cyanohydrin formation can become genuinely unfavorable — the steric strain introduced by forcing a fourth substituent (the newly added CN and OH groups) onto an already crowded carbon can outweigh whatever electronic driving force exists, shifting the reaction back toward the free ketone and HCN rather than the cyanohydrin product. This is a useful, concrete illustration of a principle worth remembering broadly: not every nucleophilic addition proceeds equally well on every carbonyl substrate, and steric hindrance specifically can make an otherwise favorable addition reaction reversible in the wrong direction.
🧪 Lab Application
You need to extend acetaldehyde by one carbon and ultimately convert that new carbon into a carboxylic acid group, via a cyanohydrin intermediate.
1
Confirm acetaldehyde is a favorable substrate. As a simple, unhindered aldehyde, acetaldehyde is expected to form its cyanohydrin readily and with a favorable equilibrium.
2
Add HCN (with NaCN or KCN) to form the cyanohydrin. Cyanide attacks the carbonyl carbon via standard nucleophilic addition, giving 2-hydroxypropanenitrile (acetaldehyde cyanohydrin) after protonation.
3
Hydrolyze the nitrile group to a carboxylic acid. Treating the cyanohydrin with aqueous acid or base converts the -CN group into a -COOH group.
4
Confirm the final product. The result is 2-hydroxypropanoic acid (lactic acid) — the original two-carbon acetaldehyde now extended by one carbon and bearing both a hydroxyl and a carboxylic acid group.
📌 Exam Application
Exams frequently test the two downstream fates of a cyanohydrin's nitrile group (hydrolysis to a carboxylic acid, or reduction to an amine) as a follow-up to the initial addition — always be ready to carry a cyanohydrin synthesis question through to one of these two further transformations, not just the initial addition step.
⚠️ Most Common Cyanohydrin Synthesis Mistakes
The most common mistake is assuming cyanohydrin formation works equally well on any carbonyl substrate, forgetting that hindered ketones specifically can have an unfavorable equilibrium that disfavors the cyanohydrin product. The other frequent trap is confusing the two possible downstream transformations of the nitrile group — hydrolysis gives a carboxylic acid, while reduction (a different set of reagents entirely) gives a primary amine.
✓ Quick Self-Test
1) What is a cyanohydrin, structurally? 2) Why does a cyanohydrin represent a genuine one-carbon chain extension? 3) What two downstream transformations can convert a cyanohydrin's nitrile group into a different functional group? 4) Why do aldehydes generally react more readily than ketones in cyanohydrin formation? 5) Why can the equilibrium for cyanohydrin formation become unfavorable with a hindered ketone?
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Wittig Reaction
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