+ Math: Algebra

Memory tricks for algebra

Linear equations, quadratics, factoring, systems, functions, and algebraic properties.

Algebra

Memory Tricks

Proven Mnemonics & Acronyms β€” fast to learn, hard to forget.

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πŸ”’ Algebra
FOIL
First Β· Outer Β· Inner Β· Last β€” multiplying two binomials
Expand (a+b)(c+d) every time without mistakes
First, Outer, Inner, Last. Every binomial multiplication follows this exact order. Never miss a term again.
F
First β€” multiply the first terms of each binomial
O
Outer β€” multiply the outermost terms
I
Inner β€” multiply the innermost terms
L
Last β€” multiply the last terms of each binomial
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πŸƒ Algebra
FOIL
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πŸƒ Answer
FFirst β€” multiply the first terms of each binomial
OOuter β€” multiply the outermost terms
IInner β€” multiply the innermost terms
LLast β€” multiply the last terms of each binomial
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πŸ”’ Algebra
Please Excuse My Dear Aunt Sally
PEMDAS β€” Parentheses Β· Exponents Β· Multiply Β· Divide Β· Add Β· Subtract
Never solve a multi-step problem in the wrong order again
When a math problem has multiple operations, solve them in PEMDAS order. The most common mistake: M/D and A/S are equal priority β€” work left to right when you reach those levels.
P
Parentheses β€” solve everything inside ( ) first
E
Exponents β€” handle all powers and roots next
M/D
Multiplication and Division β€” left to right, equal priority
A/S
Addition and Subtraction β€” left to right, equal priority
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πŸƒ Algebra
Please Excuse My Dear Aunt Sally
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πŸƒ Answer
PParentheses β€” solve everything inside ( ) first
EExponents β€” handle all powers and roots next
M/DMultiplication and Division β€” left to right, equal priority
A/SAddition and Subtraction β€” left to right, equal priority
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πŸ”’ Algebra
STAR
Search Β· Translate Β· Answer Β· Review β€” word problem strategy
Never get lost in a word problem again
Word problems feel overwhelming because students jump straight to solving. STAR slows you down and keeps you on track every time.
S
Search β€” read carefully, identify what's being asked
T
Translate β€” convert words into a math equation
A
Answer β€” solve the equation
R
Review β€” check your answer makes sense in context
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πŸƒ Algebra
STAR
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πŸƒ Answer
SSearch β€” read carefully, identify what's being asked
TTranslate β€” convert words into a math equation
AAnswer β€” solve the equation
RReview β€” check your answer makes sense in context
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πŸ”’ Algebra
Slope = Rise / Run
Slope Formula β€” (yβ‚‚βˆ’y₁) / (xβ‚‚βˆ’x₁)
Never confuse rise and run again
Rise is the vertical change (yβ‚‚βˆ’y₁). Run is the horizontal change (xβ‚‚βˆ’x₁). Think: you rise UP before you run ACROSS. Positive slope goes up left-to-right; negative slope goes down.
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πŸƒ Algebra
Slope β€” the formula?
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πŸƒ Answer
Slope = Rise / Run
Slope Formula β€” (yβ‚‚βˆ’y₁) / (xβ‚‚βˆ’x₁) β€” Rise is the vertical change (yβ‚‚βˆ’y₁). Run is the horizontal change (xβ‚‚βˆ’x₁). Think: you rise UP before you run ACROSS. Positive slope goes up left-to-right; negative slope goes down.
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πŸ”’ Algebra Β· Factoring
aΒ²βˆ’bΒ² = (a+b)(aβˆ’b)
Difference of Squares β€” two perfect squares being subtracted
Factor any difference of two perfect squares instantly
Spot two perfect squares being subtracted? Factor immediately: aΒ²βˆ’bΒ²=(a+b)(aβˆ’b). Example: xΒ²βˆ’9=(x+3)(xβˆ’3). This pattern appears on every algebra exam.
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πŸƒ Algebra Β· Factoring
How do you factor a difference of squares?
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πŸƒ Answer
Difference of Squares β€” two perfect squares being subtracted β€” Spot two perfect squares being subtracted? Factor immediately: aΒ²βˆ’bΒ²=(a+b)(aβˆ’b). Example: xΒ²βˆ’9=(x+3)(xβˆ’3). This pattern appears on every algebra exam.
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πŸ”’ Algebra Β· Factoring
Slide and Divide
Factoring ax²+bx+c when a≠1
Factor hard trinomials with a leading coefficient
Multiply a and c together (slide). Factor that product with b. Divide by a and simplify. Works every time for trinomials where the leading coefficient isn't 1.
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πŸƒ Algebra Β· Factoring
Slide and Divide
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πŸƒ Answer
Factoring ax²+bx+c when a≠1 — Multiply a and c together (slide). Factor that product with b. Divide by a and simplify. Works every time for trinomials where the leading coefficient isn't 1.
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πŸ”’ Algebra Β· Quadratics
x = (βˆ’b Β± √(bΒ²βˆ’4ac)) / 2a
Quadratic Formula β€” solves any axΒ²+bx+c=0
Solve any quadratic β€” memorize this cold
Sing to "Pop Goes the Weasel": "x equals negative b, plus or minus square root, b squared minus 4ac, all over 2a." Discriminant bΒ²βˆ’4ac: positive=2 real roots, zero=1 root, negative=no real roots.
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πŸƒ Algebra Β· Quadratics
The quadratic formula?
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πŸƒ Answer
x = (βˆ’b Β± √(bΒ²βˆ’4ac)) / 2a
Quadratic Formula β€” solves any axΒ²+bx+c=0 β€” Sing to "Pop Goes the Weasel": "x equals negative b, plus or minus square root, b squared minus 4ac, all over 2a." Discriminant bΒ²βˆ’4ac: positive=2 real roots, zero=1 root, negative=no real roots.
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πŸ”’ Algebra
Zero Product Property: if AB=0 then A=0 or B=0
Zero Product Property β€” the foundation of factoring to solve
If a product equals zero, at least one factor must be zero
Set each factor equal to zero and solve. (xβˆ’5)(x+4)=0 β†’ x=5 or x=βˆ’4. This is why factoring works for solving quadratics β€” factor first, then apply zero product property.
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πŸƒ Algebra
The zero product property?
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πŸƒ Answer
Zero Product Property: if AB=0 then A=0 or B=0
Zero Product Property β€” the foundation of factoring to solve β€” Set each factor equal to zero and solve. (xβˆ’5)(x+4)=0 β†’ x=5 or x=βˆ’4. This is why factoring works for solving quadratics β€” factor first, then apply zero product property.
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πŸ”’ Algebra Β· Inequalities
Flip the sign when Γ· or Γ— by a NEGATIVE
Inequality Sign-Flip Rule β€” the one rule students always forget
Never lose points on an inequality problem again
βˆ’2x > 6 β†’ divide both sides by βˆ’2 β†’ x < βˆ’3 (sign flips!). Number line: < and > use open circles. ≀ and β‰₯ use closed circles. Interval notation: x>3 is (3,∞), x≀5 is (βˆ’βˆž,5].
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πŸƒ Algebra Β· Inequalities
Inequalities β€” when does the sign flip?
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πŸƒ Answer
Flip the sign when Γ· or Γ— by a NEGATIVE
Inequality Sign-Flip Rule β€” the one rule students always forget β€” βˆ’2x > 6 β†’ divide both sides by βˆ’2 β†’ x < βˆ’3 (sign flips!). Number line: < and > use open circles. ≀ and β‰₯ use closed circles. Interval notation: x>3 is (3,∞), x≀5 is (βˆ’βˆž,5].
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πŸ”’ Algebra Β· Exponents
AMSZ: Add Β· Subtract Β· Multiply Β· Zero
Exponent Rules β€” Add (Γ—same base) Β· Subtract (Γ·same base) Β· Multiply (powerΒ²) Β· Zero (=1)
Four exponent rules that cover almost every problem
Multiply same base β†’ ADD exponents (xΒ³Β·x⁴=x⁷). Divide same base β†’ SUBTRACT (x⁢÷xΒ²=x⁴). Power to a power β†’ MULTIPLY (xΒ³)⁴=xΒΉΒ². Anything to ZERO = 1 (7⁰=1).
A (Add)
xᡃ Β· xᡇ = xᡃ⁺ᡇ β€” multiply same base, add exponents
S (Subtract)
xᡃ Γ· xᡇ = xᡃ⁻ᡇ β€” divide same base, subtract exponents
M (Multiply)
(xᡃ)ᡇ = xᡃᡇ β€” power to a power, multiply exponents
Z (Zero)
x⁰ = 1 β€” anything to the zero power equals one
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πŸƒ Algebra Β· Exponents
AMSZ: Add Β· Subtract Β· Multiply Β· Zero
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πŸƒ Answer
A (Add)xᡃ Β· xᡇ = xᡃ⁺ᡇ β€” multiply same base, add exponents
S (Subtract)xᡃ Γ· xᡇ = xᡃ⁻ᡇ β€” divide same base, subtract exponents
M (Multiply)(xᡃ)ᡇ = xᡃᡇ β€” power to a power, multiply exponents
Z (Zero)x⁰ = 1 β€” anything to the zero power equals one
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πŸ”’ Algebra Β· Systems
SE: Substitution Β· Elimination
Two Methods for Systems β€” Substitution (plug in) Β· Elimination (add/subtract rows)
Two reliable methods for solving any linear system
Substitution: isolate one variable, plug into the other equation β€” best when one variable is already isolated. Elimination: multiply equations to match coefficients, then add/subtract to cancel one variable.
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πŸƒ Algebra Β· Systems
SE: Substitution Β· Elimination
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πŸƒ Answer
Two Methods for Systems β€” Substitution (plug in) Β· Elimination (add/subtract rows) β€” Substitution: isolate one variable, plug into the other equation β€” best when one variable is already isolated. Elimination: multiply equations to match coefficients, then add/subtract to cancel one variable.
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πŸ”’ Algebra Β· Signs
Good Γ— Bad = Bad. Bad Γ— Bad = Good.
Multiplication Sign Rules β€” positive Γ— negative = negative Β· negative Γ— negative = positive
The "Good/Bad Person" trick β€” never mix up signs again
Positive = good person, negative = bad person. Good thing to a good person = good (+Γ—+=+). Bad thing to a bad person = also good (βˆ’Γ—βˆ’=+). Good thing to a bad person = bad (+Γ—βˆ’=βˆ’).
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πŸƒ Algebra Β· Signs
Multiplying signs β€” positive and negative rules?
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πŸƒ Answer
Good Γ— Bad = Bad. Bad Γ— Bad = Good.
Multiplication Sign Rules β€” positive Γ— negative = negative Β· negative Γ— negative = positive β€” Positive = good person, negative = bad person. Good thing to a good person = good (+Γ—+=+). Bad thing to a bad person = also good (βˆ’Γ—βˆ’=+). Good thing to a bad person = bad (+Γ—βˆ’=βˆ’).
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Absolute Value Equations
|x| = k gives x = k OR x = -k. Always split into TWO equations. Check both answers.
Absolute value means distance from zero β€” so there are always two cases
Isolate the absolute value first, then split into plus and minus cases
Step 1: Isolate |expression|. Step 2: Split into expr = +k AND expr = -k. Step 3: Solve both. Step 4: Check for extraneous solutions. Special: |x| = 0 has one solution. |x| = negative has NO solution. |x| less than k means -k less than x less than k. |x| greater than k means x less than -k OR x greater than k.
Isolate first
Get |expr| alone before splitting
Two cases
expr = k AND expr = -k β€” both must be solved
No solution
|x| = negative number is impossible β€” write No Solution
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πŸƒ Absolute Value Equations
Absolute value equations β€” how do you solve |x| = k?
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πŸƒ Answer
|x| = k gives x = k OR x = -k. Always split into TWO equations. Check both answers.
Isolate firstGet |expr| alone before splitting
Two casesexpr = k AND expr = -k β€” both must be solved
No solution|x| = negative number is impossible β€” write No Solution
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Function Composition
f(g(x)) means work inside out. g goes first, f goes second. Order matters.
Substitute the entire inner function into the outer function
To find f(g(x)): plug g(x) everywhere you see x in f
f(g(x)): substitute g(x) into f. Example: f(x) = x squared + 1, g(x) = 3x gives f(g(x)) = 9x squared + 1. Domain: x must be in domain of g AND g(x) must be in domain of f. Inverse check: f(g(x)) = g(f(x)) = x means they are inverses. Finding inverse: swap x and y, solve for y.
Inside out
Evaluate inner function first, plug result into outer
Order matters
f(g(x)) does not equal g(f(x)) in general
Inverse check
Both compositions give x means they are inverse functions
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πŸƒ Function Composition
Composite functions β€” which function goes first in f(g(x))?
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πŸƒ Answer
f(g(x)) means work inside out. g goes first, f goes second. Order matters.
Inside outEvaluate inner function first, plug result into outer
Order mattersf(g(x)) does not equal g(f(x)) in general
Inverse checkBoth compositions give x means they are inverse functions
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Rational Expressions
Factor EVERYTHING first. Cancel common factors. State restrictions BEFORE canceling.
The denominator can never be zero β€” state all restrictions from the original
Factor fully, state restrictions, then cancel β€” in that order
Simplify: factor fully, cancel common factors, state all restrictions. Multiply: factor all, cancel across, multiply remaining. Divide: Keep-Change-Flip then multiply. Add/Subtract: find LCD, convert, combine numerators, simplify. Restriction rule: set every original denominator not equal to zero before canceling anything.
Factor first
Always factor completely before doing anything else
Restrictions
Set every original denominator not equal to zero
Division
Keep-Change-Flip β€” multiply by the reciprocal
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πŸƒ Rational Expressions
Simplifying rational expressions β€” the steps?
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πŸƒ Answer
Factor EVERYTHING first. Cancel common factors. State restrictions BEFORE canceling.
Factor firstAlways factor completely before doing anything else
RestrictionsSet every original denominator not equal to zero
DivisionKeep-Change-Flip β€” multiply by the reciprocal
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Polynomial Long Division
DMSB β€” Divide, Multiply, Subtract, Bring down. Repeat until remainder degree is less than divisor.
Dividing polynomials the same way you do long division with numbers
Remainder Theorem: f(r) equals the remainder when dividing by (x minus r)
Steps: Divide leading terms, multiply result by divisor, subtract, bring down. Repeat. Synthetic division shortcut works when dividing by (x minus r). Remainder Theorem: remainder when f(x) divided by (x minus r) equals f(r). Factor Theorem: (x minus r) is a factor if and only if f(r) equals zero.
DMSB
Divide, Multiply, Subtract, Bring down β€” repeat
Remainder Theorem
f(r) equals the remainder when dividing by (x minus r)
Factor Theorem
f(r) equals zero means (x minus r) is a factor
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πŸƒ Polynomial Long Division
DMSB
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πŸƒ Answer
DMSB β€” Divide, Multiply, Subtract, Bring down. Repeat until remainder degree is less than divisor.
DMSBDivide, Multiply, Subtract, Bring down β€” repeat
Remainder Theoremf(r) equals the remainder when dividing by (x minus r)
Factor Theoremf(r) equals zero means (x minus r) is a factor
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Complex Numbers
i squared = -1. Powers cycle every 4: i, -1, -i, 1. Divide exponent by 4 and use the remainder.
Imaginary and complex numbers β€” arithmetic with the square root of negative one
To divide complex numbers, multiply top and bottom by the conjugate of the denominator
Powers of i cycle: i to the 1 = i, squared = -1, cubed = -i, fourth = 1. For i to the n: divide n by 4 and use remainder (0 gives 1, 1 gives i, 2 gives -1, 3 gives -i). Add/Subtract: combine real and imaginary parts separately. Multiply: FOIL then replace i squared with -1. Divide: multiply by conjugate (a minus bi) to eliminate i from denominator.
Powers of i
Cycle of 4: i, -1, -i, 1. Use remainder of exponent divided by 4.
Multiply
FOIL then replace i squared with -1
Divide
Multiply by conjugate (a minus bi) to get real denominator
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πŸƒ Complex Numbers
Powers of i β€” the pattern?
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πŸƒ Answer
i squared = -1. Powers cycle every 4: i, -1, -i, 1. Divide exponent by 4 and use the remainder.
Powers of iCycle of 4: i, -1, -i, 1. Use remainder of exponent divided by 4.
MultiplyFOIL then replace i squared with -1
DivideMultiply by conjugate (a minus bi) to get real denominator
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Radical Equations
Isolate the radical. Raise BOTH sides to the index power. ALWAYS check for extraneous solutions.
Solving equations containing square roots, cube roots, or nth roots
Squaring both sides can introduce false solutions β€” checking is not optional
Steps: Isolate the radical. Raise both sides to the power matching the index. Solve the resulting equation. CHECK every answer in the original. Two radicals: isolate one, raise to power, isolate second, raise to power again. Even root of a negative has no real solution.
Isolate first
Get the radical alone before raising to a power
Power matches index
Square root needs squaring, cube root needs cubing
CHECK always
Extraneous solutions appear often β€” never skip the check
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πŸƒ Radical Equations
Solving radical equations β€” the steps?
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πŸƒ Answer
Isolate the radical. Raise BOTH sides to the index power. ALWAYS check for extraneous solutions.
Isolate firstGet the radical alone before raising to a power
Power matches indexSquare root needs squaring, cube root needs cubing
CHECK alwaysExtraneous solutions appear often β€” never skip the check
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